by Guest » Fri Jul 14, 2023 12:44 am
an arithmetic sequence of integers has an even number of terms, a1, a2, ....a2n, where n≥1. When these are added together the result a1+a2+.....+a2n-1+a2n=2000. when the odd-position terms are added, the result is a1+a3+....+a2n-1=968. How many terms could this sequence have?