Find the value - older math olympiad question Help :)

Find the value - older math olympiad question Help :)

Find the value $$a^3b^7c^{14}=$$
$$a^3b^2c=108$$,
$$a^2b^3c^5=240$$
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Re: Find the value - older math olympiad question Help :)

Can you show some work? Thanks

kasia

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Re: Find the value - older math olympiad question Help :)

We notice that :

$$\frac{(a^{2}b^{3}c^{5})^{3}}{a^{3}b^{2}c}$$=$$\frac{a^{6}b^{9}c^{15}}{a^{3}b^{2}c}$$

We received $$\frac{(a^{2}b^{3}c^{5})^{3}}{a^{3}b^{2}c}$$=$$a^{3}$$$$b^{7}$$$$c^{14}$$

$$\frac{240^{3}}{108}$$=$$a^{3}$$$$b^{7}$$$$c^{14}$$

$$a^{3}$$$$b^{7}$$$$c^{14}$$=$$\frac{13 824 000}{108}$$=128 000
Guest

Re: Find the value - older math olympiad question Help :)

thank you!

kasia

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Joined: Sun Aug 04, 2019 12:12 pm
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