Prove this using trigonometric identities

Prove this using trigonometric identities

Postby nazz » Thu May 30, 2019 12:18 pm


[tex]\frac{1}{1+sinx}[/tex] = [tex]\frac{secx-sinxsecx}{cosx}[/tex]
Prove this using identities.
nazz
 
Posts: 1
Joined: Thu May 30, 2019 12:11 pm
Reputation: 0

Re: Prove this using trigonometric identities

Postby nathi123 » Fri May 31, 2019 5:05 am

[tex]secx=\frac{1}{cosx}\Rightarrow \frac{1}{cosx}.\frac{1-sinx}{cosx}=\frac{1-sinx}{cos^{2}x}=\frac{1-sinx}{1-sin^{2}x}=\frac{1}{1+sinx}[/tex]

nathi123
 
Posts: 19
Joined: Sun Sep 17, 2017 1:56 pm
Reputation: 16

Re: Prove this using trigonometric identities

Postby nathi123 » Sun Jun 02, 2019 4:34 am

A=[tex]\frac{secx-sinxsecx}{cosx}=\frac{secx(1-sinx)}{cosx}=\frac{1-sinx}{cos^{2}x}=\frac{1-sinx}{(1-sinx)(1+sinx)}=\frac{1}{1+sinx}[/tex]
[tex]secx=\frac{1}{cosx}[/tex].

nathi123
 
Posts: 19
Joined: Sun Sep 17, 2017 1:56 pm
Reputation: 16


Return to Math Problem of the Week



Who is online

Users browsing this forum: No registered users and 1 guest