Find the exact value of the logarithmic expession

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Find the exact value of the logarithmic expession

Postby Math Tutor » Thu Nov 10, 2011 7:56 am

[tex]log_{12}18*log_{24}54 + 5(log_{12}18 - log_{24}54) = ?[/tex]
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Re: Find the exact value of the logarithmic expession

Postby Guest » Sat Nov 12, 2011 4:28 pm

1? tell me if its correct and i am going to write the whole solution tomorrow ;]
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Re: Find the exact value of the logarithmic expession

Postby Math Tutor » Sat Nov 12, 2011 5:13 pm

Yes, It is correct!

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Re: Find the exact value of the logarithmic expession

Postby Guest » Sat Nov 12, 2011 5:20 pm

[tex]\frac {log_{3} 18}{ log_{3} 12 }[/tex]
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Re: Find the exact value of the logarithmic expession

Postby Guest » Sat Nov 12, 2011 5:26 pm

i meant to take a preview with the last post sry clicked submit by accident
...
we need to change the base to 3 after that we need to use [tex]log_{a}{bc}=log_{a}b +log_{a}c[/tex]

than the expression will have ingegers only and [tex]log_{3}2[/tex]
for the sake of simplicity lets say that [tex]log_{3}2=b[/tex]

after simplifying the expression we get [tex]\frac {6b^2+5b+1}{6b^2+5b+1}=1[/tex]
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Re: Find the exact value of the logarithmic expession

Postby Guest » Tue Nov 15, 2011 2:05 pm

The question is: how do you figure out that the answer is 1 without doing any additional calculations? YS
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Re: Find the exact value of the logarithmic expession

Postby Guest » Tue Nov 15, 2011 3:31 pm

By the way I also does not understand your calculations.
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Re: Find the exact value of the logarithmic expession

Postby Guest » Fri Nov 25, 2011 6:27 pm

just change the base to 3 and use this [tex]log_{a}{bc}=log_{a}b +log_{a}c[/tex] and you will understand everything....
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