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Solve the equation

Postby shiwani » Mon Jan 14, 2019 6:39 am

Solve the equation:- 2[tex]\sqrt{x}[/tex] =x +1
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Re: Solve the equation

Postby nathi123 » Mon Jan 14, 2019 2:29 pm

[tex]\begin{array}{|l} 2\sqrt{x} =x+1\\ x \ge 0\Rightarrow x+1>0\end{array}\Leftrightarrow 4x=(x+1)^{2}\Leftrightarrow x^{2}-2x+1=0\Leftrightarrow (x-1)^{2}=0\cap x\ge 0[/tex]
[tex]\Leftrightarrow x_{1 }=x_{2 }=1[/tex]

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