by Guest » Sun Jan 31, 2016 7:08 am
A plot of the graph [tex]y=2(x-1)^9(x+1)^8-1[/tex] should convince you there is only one root (a root for this graph corresponds to a solution of the original equation). Formally proving this fact involves finding the turning points which are at [tex]x=-1,-1/17[/tex] and [tex]1[/tex] and showing that they all have [tex]y[/tex] values below [tex]0[/tex], and since [tex]y[/tex] is a polynomial of odd degree and the coefficient of the monomial of highest degree is positive, it can only have crossed the [tex]x[/tex]-axis once.
The root is between [tex]1[/tex] and [tex]2[/tex] (as the [tex]y[/tex] value changes from negative to positive). To get a more accurate answer you can use Newton-Raphson with an initial guess of 1.5:
[tex]x_0=1.5[/tex]
[tex]x_{n+1} = x_{n} -\frac{2(x_n-1)^9(x_n+1)^8-1}{2(17x_n+1)(x_n-1)^8(x_n+1)^7}[/tex]
Which gives (using a computer):
[tex]x_{1} = 1.4607439698113207[/tex]
[tex]x_{2} = 1.434299330659228[/tex]
[tex]x_{3} = 1.4233741563856475[/tex]
[tex]x_{4} = 1.421818929333896[/tex]
[tex]x_{5} = 1.4217910964455613[/tex]
[tex]x_{6} = 1.421791087714604[/tex]
[tex]x_{7} = 1.4217910877146032[/tex]
[tex]x_{8} = 1.4217910877146032[/tex]
[tex]x_{9} = 1.4217910877146032[/tex]
[tex]x_{10} = 1.4217910877146032[/tex]
As you can see the value converges and appears to be accurate to 16 decimal places after the 7th iteration.
I'm afraid there isn't an exact answer (involving simple operations like square roots and arithmetic operators on integers), the best we can do is give a numerical approximation.
Hope this helped,
R. Baber.