Find (a + b)/a

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Find (a + b)/a

Postby nycmath » Thu Aug 20, 2026 11:01 pm

See attachment. Show your work in step by step fashion. Enjoy.
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nycmath
 
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Re: Find (a + b)/a

Postby Eigenvalue » Fri Aug 21, 2026 8:37 pm

a³=27

[tex]\sqrt[3]{a³}[/tex]=[tex]\sqrt[3]{27}[/tex]

a=3

b²=36

b=[tex]\pm[/tex]6

If a=3 and b=6:

[tex]\frac{a+b}{a}[/tex]=[tex]\frac{9}{3}[/tex]=3

if a=3 and b=-6:

[tex]\frac{a+b}{a}[/tex]=[tex]\frac{3-6}{3}[/tex]=-1

Eigenvalue
 
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Re: Find (a + b)/a

Postby nycmath » Fri Aug 21, 2026 10:19 pm

Eigenvalue wrote:a³=27

[tex]\sqrt[3]{a³}[/tex]=[tex]\sqrt[3]{27}[/tex]

a=3

b²=36

b=[tex]\pm[/tex]6

If a=3 and b=6:

[tex]\frac{a+b}{a}[/tex]=[tex]\frac{9}{3}[/tex]=3

if a=3 and b=-6:

[tex]\frac{a+b}{a}[/tex]=[tex]\frac{3-6}{3}[/tex]=-1


Neatly done in vertical form. I love it.

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