Eigenvalue wrote:a³=27
[tex]\sqrt[3]{a³}[/tex]=[tex]\sqrt[3]{27}[/tex]
a=3
b²=36
b=[tex]\pm[/tex]6
If a=3 and b=6:
[tex]\frac{a+b}{a}[/tex]=[tex]\frac{9}{3}[/tex]=3
if a=3 and b=-6:
[tex]\frac{a+b}{a}[/tex]=[tex]\frac{3-6}{3}[/tex]=-1
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