No, 875 is not correct. Your method of breaking the problem into the possible team-size patterns is the right approach, but the counting in cases B and C needs correction.
The possible distributions are:
**A) 4,1,1,1**
Choose the group of 4 people:
C(7,4) = 35
**B) 3,2,1,1**
Choose the group of 3, then the group of 2, and the remaining two people form the single-person teams:
C(7,3) × C(4,2) × C(2,1) ÷ 2! = 210
(The division by 2! avoids counting the two identical single-person teams twice.)
**C) 2,2,2,1**
Choose the single person, then divide the remaining 6 people into three pairs:
7 × (6! ÷ (2!² × 3!)) = 105
Therefore, the total number of ways is:
35 + 210 + 105 = **350**
So the correct answer is **350**, not 875.
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https://longdivcalc.com/