by Guest » Fri Jun 19, 2020 7:38 am
That's a good point- though it would have been better for the OP to have explicitly said so!!
If the formula is to be y= mn^x then we have two parameters to be determine, m and n. And we need two equations to do that. Here we have six, which is "overkill". It is quite possible that the answer will depend on which two data points we take- that the formula is NOT precisely "y= mn^x" for any m and n.
If I suspect such a situation, I am inclined to use the two data points farthest apart to make it as general as possible. Here, those are (0.5, 0.53) and (3.0, 46.77).
So we have [tex]0.53= mn^{0.5}[/tex] and [tex]46.77= mn^3[/tex]. We can eliminate "m" from the equations by dividing the second by the first: [tex]\frac{46.77}{0.53}= \frac{mn^{3}}{mn^{0.5}}[/tex] or [tex]88.24= n^{3- 0.5}= n^{2.5}[/tex]. Taking the 2.5 root of both sides, [tex]n= 35.30[/tex]. Then [tex]46.77= m(35.30^3)= 43980m[/tex] so [tex]m= \frac{46.77}{43980}= 0.001063[/tex].
Another idea is to use "least squares" to find a curve, y= mn^x the comes closest to all points without necessarily going through any of them.