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Logarithms problems.
by alg » Thu Mar 05, 2020 6:50 pm
Convert to exponential form
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alg
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by HallsofIvy » Mon Mar 09, 2020 5:05 pm
Do you not know what a "logarithm" is? if [tex]y= log_a(x)[/tex] then, by definition, [tex]x= a^y[/tex].
So if [tex]y= log_2(x- 2)=[/tex] then [tex]x- 2= 2^y[/tex] and [tex]x= 2+ 2^y[/tex].
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HallsofIvy
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