Solution:
Let us say first number is n. So the second number shall be (30-n)
multiply the second number by 2, it yields = 2 (30 - n). This is ‘equal’ to 6 more than 4 times the first number (n). Say (4n + 6)
Thus we have 2(30-n) = 4n + 6
60 - 2n = 4n + 6
54 = 6n
n = 9
so first number is 9 and the other number is (30 - 9) = 21
We can check it now: 2(21) = 42 & 4(9) = 36, and one is 6 more than the other.
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