Logarithmic problem

[Guest]

solve for x:11^(4x-5) * 3^(2x)=5^(3-x)*7^(-x)..plss give give the explation of this solution

[Guest]

Depends on how you want to solve it..........

Just take logs to base 10 to form the expression

log 11(4x - 5) + log 3(2x) = log 5(3-x) + log 7(-x)

Find the logs values on your calculator........

1.04(4x - 5) + 0.477(2x) = 0.699(3-x) + 0.845(-x)

It is now an ordinary algebriac equation to solve for x ...............