Help required with calculus problem

[burgess]

What is the value of log[i*pi/2] ?

How can we solve this problem? Please tell me the procedure

[Guest]

If [tex]\alpha[/tex] is a complex number then log[tex]\alpha[/tex]=ln(mod([tex]\alpha[/tex]))+i*arg[tex]\alpha[/tex].
mod(i*[tex]\pi[/tex]/2)=[tex]\pi[/tex]/2.
arg(i*[tex]\pi[/tex]/2)=[tex]\pi[/tex]/2.
[tex]\Rightarrow[/tex] log(i*[tex]\pi[/tex]/2)=ln([tex]\pi[/tex]/2)+i*[tex]\pi[/tex]/2