A body is falling freely without a beginning speed from height H and the last h = 60 m passes for time t<sub>1</sub> = 2 s.

a) What is the time of falling of the ball?

b) How many meters is the height H?

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A body is falling freely without a beginning speed from height H and the last h = 60 m passes for time t<sub>1</sub> = 2 s.

a) What is the time of falling of the ball?

b) How many meters is the height H?

a) What is the time of falling of the ball?

b) How many meters is the height H?

[tex]D = \frac{1}{ 2}g(T^2 - t^2)[/tex]

So we can set up a system of two equations based on the given information:

[tex]60 = \frac{1}{2}g(T^2 - t^2)[/tex] ......................(1)

[tex]T - t = 2[/tex] .....................................................(2)

Solving for T and t, we have

[tex]T = 1 +\frac{30}{g} = 4[/tex]

[tex]t = T - 2 = 2[/tex]

[tex]H = \frac{1}{2}gT^2 = \frac{1}{2}g4^2 = 80[/tex]

So

It take the body 4 seconds to fall 80 meters

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