Help!!! A complex problem...

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Help!!! A complex problem...

Postby Guest » Wed Feb 27, 2013 12:37 pm

Hi people,

This is a really confusing question (i couldn't solve it)- is anybody out there who can solve this? :?

A sold his bike to B at a loss of 28%. B spent 1680$ on its repairs and sold the bike to C for 35910$, Thereby making a profit of 12.5%, find the cost price of the bike for A.

hope someone solves it!





Guest
 

Re: Help!!! A complex problem...

Postby Guest » Thu Feb 28, 2013 9:31 am

Let x be the cost of the bike for A.

A sells it to B with a 28% loss
So B pays (1-28/100)x = 0.72x

B spends $1680, so he has now spent 0.72x+1680

B sells it to C making a 12.5% profit.
So B sells it to C for (1+12.5/100)(0.72x+1680) = 1.125(0.72x+1680) = 0.81x+1890

We are told C paid $35910,
So 0.81x+1890 = 35910
x = (35910 - 1890)/0.81 = 42000

So A paid $42000

(We could have also just worked backward. B sold the bike for 35910 and made 12.5% profit, so it originally cost him 35910/1.125 = 31920. B spent 1680 on repairs, so before repairs it cost him 31920-1680 = 30240. A sold it for 30240 which was a 28% loss, so it originally cost 30240/0.72 = 42000.)

Hope this helped,

R. Baber.

Guest
 


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