by Guest » Tue Mar 26, 2024 7:18 am
We're tasked with finding the dimensions of a Norman window of maximum area given that the total perimeter is 22 feet, and the radius of the semicircle is x/2, where x is the width of the rectangular part of the window.
Let's denote the width of the rectangle as x and its height as y, and the radius of the semicircle as x/2. We need to maximize the area A of the window, which is the sum of the area of the rectangle and the semicircle:
A=xy+πx^2/4
We are also given that the total perimeter is 22 feet:
2x+y+π*x/2=22
Now, we need to express y in terms of x using the perimeter equation:
y=22−2x−πx/2
Substitute this expression for y into the area equation:
A(x)=x(22−2x−πx/2)+πx^2/4
Now, we need to find the critical points of A(x) by taking the derivative with respect to x and setting it equal to zero:
dA/dx=22−6x−3πx/2=0
Solving this equation will give us the critical points. Once we have those, we can determine which one maximizes the area A.
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