Number combinations given certain criteria

[Guest]

Hi,

Using my "real life" example below but also considering the numerals used can be anything, how do you calculate the number of combinations given the following criteria:

5 out of 50 numbers chosen (50! /(5!*(50-5)!)

1) less or equal to 2 numbers can be odd (((48/2+1)! /(0!*((48/2+1)-0)!) * ((50/2)! /((5-0)!*((50/2)-(5-0))!)) + (((48/2+1)! /(1!*((48/2+1)-1)!) * ((50/2)! /((5-1)!*((50/2)-(5-1))!)) + (((48/2+1)! /(2!*((48/2+1)-2)!) * ((50/2)! /((5-2)!*((50/2)-(5-2))!))

2) less or equal to 1 number can be from a set of 6 numbers (e.g. 1,4,6,7,22,40) = ((6! /(0!*(6-0)!) * ((50-6)! /((5-0)!*((50-6)-(5-0))!)) + ((6! /(1!*(6-1)!) * ((50-6)! /((5-1)!*((50-6)-(5-1))!))

I can calculate the above for 2) or 3), but not when both meet the criteria together. Sorry for lack of algebra as mine is appalling. Appreciate any expert's help!!!