Straight:
The only difference is that the top rank can bridge the 1st rank to form a sequence. Think of it as if Q, K, A, 2, 3 was a legal straight. How is that calculated?
A more complex straight:
This one gets tricky, I think.
In this variant, there are:
64 cards
4 suits
13 ranks
Ranks 1-12 have 4 cards per rank
However, rank 13 has 16 cards
Any rank 13 card would still have the bridging ability to make a straight connecting the top rank with the bottom rank.
What are the odds of that kind straight?
Flush variant:
Similar to the previous, there are:
64 cards
4 suits
13 ranks
Ranks 1-12 have 4 cards per rank
Rank 13 has 16 cards
Rank 13 cards have 2 suits
4 rank 13 cards contain Hearts & Diamonds
4 rank 13 cards contain Diamonds & Spades
4 rank 13 cards contain Spades & Clubs
4 rank 13 cards contain Clubs & Hearts
Is that in essence just 4 extra cards to draw from to get a flush?
"Full Court":
This deck has a "Court" system, which is pretty much like suits. I think of Suits running vertically down the ranks while Courts run horizontally.
64 cards
4 suits - hearts, diamonds, spades, clubs
4 courts - A, B, C, D (16 cards in each court)
Court A has ranks: 1, 4, 7, 10
Court B has ranks: 2, 5, 8, 11
Court C has ranks: 3, 6, 9, 12
Court D has all 16 cards in rank 13
To have a "Full Court" (5 cards of the same court), would that be the same as calculating a more traditional flush? Or am I missing something?
Cheers!

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