Dice conditional probability question

[Guest]

In a game of Yahtzee, you roll 5 dice where order does not matter. If I roll my five dice, what's the probability that I get no 3's or no odd numbers given that I roll exactly two 2's?
I would like an explaination of the answer

[HallsofIvy]

You roll 5 dice and two of them are "2"s which are neither "3"s nor odd so this is just "what is the probability of no "3"s nor odd numbers in three rolls. Also, since "3" is odd, I am assume these are two different questions. On a single die, there are 6 numbers, 5 of them "not three". The probability that all 3 dice are "not three" is (5/6)^3. 3 of the 6 numbers, 1/2 of them, are "not odd". The probability that all 3 dice are "not odd" is (1/2)^3.

[Mathlibra]

let's visit mathlibra.com to read page
Probability of Getting anything on Rolling or Throwing Two Dice. And let's read other poges.