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Probability theory and statistics
by Chikis » Fri Jul 13, 2012 1:51 am
A box contains identical balls of which 12 are red, 16 white and 8 blue. Three balls are drawn from the box one after the other without replacement. Find the probability that: two are white and one is blue.
Please I need working and explaination.
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Chikis
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by Guest » Tue Aug 14, 2012 3:17 am
Total outcome = 12+16+8 = 36
Prob(Two are white and one is blue)
= P(WWB) or P(WBW) or P(BWW)
= (16/36*15/35*8/34) or (16/36*8/35*15/34) or (8/36*16/35*15/34)
=16/357 + 16/357 + 16/357
=16/119
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