Probability - John has 68 red marbles in one bowl

Probability theory and statistics

Probability - John has 68 red marbles in one bowl

Postby Guest » Fri Jun 09, 2017 2:49 am

John has 68 red marbles in one bowl 1 and 25 blue marbles in bowl 2. If John needed to choose five red marbles from bowl 1 and one blue marble from bowl 2, how many different possible combinations of five red and one blue marble can be chosen?
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Re: probability word problem

Postby Guest » Sat Jun 10, 2017 3:02 pm

$C_{68}^5.C_{25}^1=\frac{{\cancel{68}}^{17}.67.{{\cancel{66}}^{{\cancel{22}}^{11}}}.65.64}{1.{\cancel{2}}^1.{\cancel{3}}^1.{\cancel{4}}^1.{\cancel{5}}^1}\cdot\frac{{\cancel{25}}^5}{1}=17.67.11.65.64.5=260\ 603\ 200$
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