Value of K

[Jason76]

[tex]K(x^{6}) = 1[/tex]

[tex]\dfrac{K(x^{6})}{x^{6}} = \dfrac{1}{x^{6}}[/tex] where [tex]x \ne 0[/tex]

[tex]K = \dfrac{1}{x^{6}}[/tex]

Actually, here is the original problem:

A die has its six faces loaded so that P(roll is i)=K*x for x=1,2,3,4,5,6. It is rolled until an even number appears. Let X be the number of rolls needed.

Next finding K is needed.

[Jason76]

Contacted the professor.

A die has its six faces loaded so that P(roll is i)=K*x for x=1,2,3,4,5,6. It is rolled until an even number appears. Let X be the number of rolls needed.

Next finding K is needed.

[tex]K + 2K + 3K + 4K + 5K + 6K = 1[/tex]

is the correct format so

[tex]21K = 1[/tex]

so

[tex]K = \dfrac{1}{21}[/tex]