P(green 3 consecutive times)

Probability theory and statistics

P(green 3 consecutive times)

Postby nycmath » Thu Oct 01, 2026 10:00 pm

A bag has 20 green marbles, 15 blue marbles and 25 red marbles. What is the probability of randomly selecting a green marble three consecutive times?
nycmath
 
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Re: P(green 3 consecutive times)

Postby Eigenvalue » Fri Oct 02, 2026 1:51 am

With replacement
[tex]\frac{20}{60}[/tex]*[tex]\frac{19}{59}[/tex]*[tex]\frac{18}{58}[/tex]

=[tex]\frac{19*18}{3*2*29*59}[/tex]

=[tex]\frac{57}{1711}[/tex]

Without replacement:
[tex]\frac{20}{60}[/tex]*[tex]\frac{19}{60}[/tex]*[tex]\frac{18}{20}[/tex]

=[tex]\frac{19*9}{10*60*3}[/tex]

=[tex]\frac{57}{200}[/tex]

Eigenvalue
 
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Re: P(green 3 consecutive times)

Postby nycmath » Fri Oct 02, 2026 12:34 pm

Eigenvalue wrote:With replacement
[tex]\frac{20}{60}[/tex]*[tex]\frac{19}{59}[/tex]*[tex]\frac{18}{58}[/tex]

=[tex]\frac{19*18}{3*2*29*59}[/tex]

=[tex]\frac{57}{1711}[/tex]

Without replacement:
[tex]\frac{20}{60}[/tex]*[tex]\frac{19}{60}[/tex]*[tex]\frac{18}{20}[/tex]

=[tex]\frac{19*9}{10*60*3}[/tex]

=[tex]\frac{57}{200}[/tex]


This is a good mechanical reply but you don't explain what information in the word problem led to the right setup to find the correct answer.

nycmath
 
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Reputation: 61


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