P(blue and then green)

[nycmath]

A box has 15 blue marbles and 25 green marbles. What is the probability of randomly selecting 2 blue marbles followed by 2 green marbles?

[Eigenvalue]

Without replacement:
[tex]\frac{15}{40}[/tex]*[tex]\frac{14}{39}[/tex]*[tex]\frac{25}{38}[/tex]*[tex]\frac{24}{37}[/tex]
=[tex]\frac{3*14*25*24}{8*39*38*37}[/tex]
=[tex]\frac{9*7*25}{39*19*37}[/tex]
=[tex]\frac{525}{9139}[/tex]

With replacement:
[tex]\frac{15}{40}[/tex]*[tex]\frac{14}{40}[/tex]*[tex]\frac{25}{40}[/tex]*[tex]\frac{24}{40}[/tex]

=[tex]\frac{3}{8}[/tex]*[tex]\frac{7}{20}[/tex]*[tex]\frac{5}{8}[/tex]*[tex]\frac{3}{5}[/tex]

=[tex]\frac{3*3*7}{8*20*8}[/tex]

=[tex]\frac{63}{1280}[/tex]

[nycmath]

Without replacement:
[tex]\frac{15}{40}[/tex]*[tex]\frac{14}{39}[/tex]*[tex]\frac{25}{38}[/tex]*[tex]\frac{24}{37}[/tex]
=[tex]\frac{3*14*25*24}{8*39*38*37}[/tex]
=[tex]\frac{9*7*25}{39*19*37}[/tex]
=[tex]\frac{525}{9139}[/tex]

With replacement:
[tex]\frac{15}{40}[/tex]*[tex]\frac{14}{40}[/tex]*[tex]\frac{25}{40}[/tex]*[tex]\frac{24}{40}[/tex]

=[tex]\frac{3}{8}[/tex]*[tex]\frac{7}{20}[/tex]*[tex]\frac{5}{8}[/tex]*[tex]\frac{3}{5}[/tex]

=[tex]\frac{3*3*7}{8*20*8}[/tex]

=[tex]\frac{63}{1280}[/tex]

This is a good mechanical reply but you don't explain what information in the word problem led to the right setup to find the correct answer.