Eigenvalue wrote:Probability of x and then y[tex]\rightarrow[/tex]P(y|x)
Without replacement:
P(y|x)
=[tex]\frac{1}{26}[/tex]*[tex]\frac{1}{25}[/tex]
=[tex]\frac{1}{650}[/tex]
With replacement:
P(y|x)
=[tex]\frac{1}{26}[/tex]*[tex]\frac{1}{26}[/tex]
=[tex]\frac{1}{576}[/tex]
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