P(X and then Y)

Probability theory and statistics

P(X and then Y)

Postby nycmath » Wed Sep 30, 2026 10:45 pm

A box has 26 index cards representing the letters of the alphabet A to Z. What is the probability of randomly selecting X and then Y?
nycmath
 
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Re: P(X and then Y)

Postby Eigenvalue » Wed Sep 30, 2026 11:51 pm

Probability of x and then y[tex]\rightarrow[/tex]P(y|x)

Without replacement:
P(y|x)
=[tex]\frac{1}{26}[/tex]*[tex]\frac{1}{25}[/tex]

=[tex]\frac{1}{650}[/tex]

With replacement:
P(y|x)
=[tex]\frac{1}{26}[/tex]*[tex]\frac{1}{26}[/tex]

=[tex]\frac{1}{576}[/tex]

Eigenvalue
 
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Re: P(X and then Y)

Postby nycmath » Thu Oct 01, 2026 12:16 pm

Eigenvalue wrote:Probability of x and then y[tex]\rightarrow[/tex]P(y|x)

Without replacement:
P(y|x)
=[tex]\frac{1}{26}[/tex]*[tex]\frac{1}{25}[/tex]

=[tex]\frac{1}{650}[/tex]

With replacement:
P(y|x)
=[tex]\frac{1}{26}[/tex]*[tex]\frac{1}{26}[/tex]

=[tex]\frac{1}{576}[/tex]


I will post more probability problems later from the job.

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