Guest wrote:The only sums above 10 are 11 (two ways) and 12 (one way), so [tex]P(>10)=\frac{3}{36}=\frac{1}{12}[/tex], and [tex]P(\le 10)=1-\frac{1}{12}=\frac{11}{12}[/tex].
nycmath wrote:Guest wrote:The only sums above 10 are 11 (two ways) and 12 (one way), so [tex]P(>10)=\frac{3}{36}=\frac{1}{12}[/tex], and [tex]P(\le 10)=1-\frac{1}{12}=\frac{11}{12}[/tex].
A pair of dice are rolled. What is the probability of rolling 10 or less?
Note: We are told that the complement of rolling "10 or less" is rolling 11 or 12. What does that mean? If the question is asking for 10 or less, why is 11 or 12 involved in the calculation?
I don't understand "11 or 12" in the note given. What does 11 or 12 have to do with 10 or less?
This is why students around the globe find probability problems to be fuzzy.
Eigenvalue wrote:nycmath wrote:Guest wrote:The only sums above 10 are 11 (two ways) and 12 (one way), so [tex]P(>10)=\frac{3}{36}=\frac{1}{12}[/tex], and [tex]P(\le 10)=1-\frac{1}{12}=\frac{11}{12}[/tex].
A pair of dice are rolled. What is the probability of rolling 10 or less?
Note: We are told that the complement of rolling "10 or less" is rolling 11 or 12. What does that mean? If the question is asking for 10 or less, why is 11 or 12 involved in the calculation?
I don't understand "11 or 12" in the note given. What does 11 or 12 have to do with 10 or less?
This is why students around the globe find probability problems to be fuzzy.
If rolling a sum of 10 or less is considered one event,its complementary event is rolling an 11 or 12, as all outcomes for the sum of 2 dice are from 2 to 12.
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