by HallsofIvy » Wed Sep 23, 2020 6:59 pm
Since this is four to five months old: [tex]f(x)= 3^x[/tex], [tex]f(x+2)= 3^{x+ 2}= (3^x)(3^2)= 9(3^x)[/tex], [tex]f(x+ 3)= 3^{x+ 3}= (3^x)(3^3)= 27(3^x)[/tex], and [tex]f(x+ 4)= 3^{x+ 4}= (3^x)(3^4)= 81(3^x)[/tex].
So [tex]f(x+ 2)+ f(x+ 3)+ f(x+ 4)= 9(3^x)+ 27(3^x)+ 81(3^x)= (9+ 27+ 81)3^x= 117(3^x)[/tex].