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by Math Tutor » Tue Aug 10, 2010 8:14 am
label all intercepts and asymptotes:
[tex]y^2= x^3-4/3x[/tex]
thanks in advance as you help me with these problems.
Lazarus Mgbelu
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Math Tutor
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by adamsmith » Wed Sep 04, 2013 5:42 am
Given y=√[(x^3-4)/(3x)]
y-intercept y=0
then (0,0)
x-intercept (2^(2/3),(-2)^(2/3),(-(-1)^3/2*2^(2/3))
vertical asymptotic 3x=0
x=0
oblique asymptotic (x^3-4)/(3x)=x/√3
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