First derivative

First derivative

Postby missayhl » Sun Aug 10, 2008 3:14 am

what's the first derivative for:
[tex]x^2(x+1)^3[/tex]
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Postby Fed_BG » Sun Aug 10, 2008 6:37 am

[tex]\left[ {x^2 (x + 1)^3 } \right]' = \left( {x^2 } \right)'(x + 1)^3 + x^2 \left[ {(x + 1)^3 } \right]' = 2x(x + 1)^3 + 3x^2 (x + 1)^2[/tex]

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Postby sree » Sat Aug 23, 2008 10:10 am

hi,u can xpand (x+1) whole cube in the form of(a+b)''' and multiply it with x".then u can normally integrate. the answer is x''''''/6+3x'''''/5+3x'''''/4+x'''/3 i guess........

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Postby Fed_BG » Sun Aug 24, 2008 6:56 pm

Why are you integrating here...? The problem is to find the derivative...

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Re: first derivativ

Postby waleed432 » Thu Nov 06, 2014 8:39 am

Find the derivative of the following functions:

f(x) = 1, f'(x) = ?

[tex]f(x) = x^2 + 5x + 1[/tex], f'(x) = ?

[tex]f(x) = \frac{x^3}{x + 1}[/tex], f'(x) = ?

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