Compute

Compute

Postby nycmath » Fri Sep 25, 2026 8:50 pm

See attachment.
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nycmath
 
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Re: Compute

Postby Eigenvalue » Fri Sep 25, 2026 10:24 pm

[tex]f^{-1 }[/tex](f(x))=x

The input is [tex]\frac{22}{7}[/tex], so x=[tex]\frac{22}{7}[/tex]

f[tex]f^{-1 }[/tex](f([tex]\frac{22}{7}[/tex]))=[tex]\frac{22}{7}[/tex]

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Re: Compute

Postby nycmath » Sat Sep 26, 2026 10:48 am

Eigenvalue wrote:[tex]f^{-1 }[/tex](f(x))=x

The input is [tex]\frac{22}{7}[/tex], so x=[tex]\frac{22}{7}[/tex]

f[tex]f^{-1 }[/tex](f([tex]\frac{22}{7}[/tex]))=[tex]\frac{22}{7}[/tex]


Grease lightning!

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