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Compute
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Re: Compute
by Eigenvalue » Sat Sep 26, 2026 12:17 am
[tex]\frac{((x-3)/(x+4))-((a-3)/(a+4))}{x-a}[/tex]
=[tex]\frac{(x-3)(a+4)-(a-3)(x+4)}{(x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{ax-3a+4x-12-(ax-3x+4a-12)}{(x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{-3a+3x+4x-4a}{((x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{7}{(x+4)(a+4)}[/tex]
=[tex]\frac{(x-3)(a+4)-(a-3)(x+4)}{(x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{ax-3a+4x-12-(ax-3x+4a-12)}{(x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{-3a+3x+4x-4a}{((x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{7}{(x+4)(a+4)}[/tex]
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Re: Compute
by nycmath » Sat Sep 26, 2026 10:51 am
Eigenvalue wrote:[tex]\frac{((x-3)/(x+4))-((a-3)/(a+4))}{x-a}[/tex]
=[tex]\frac{(x-3)(a+4)-(a-3)(x+4)}{(x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{ax-3a+4x-12-(ax-3x+4a-12)}{(x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{-3a+3x+4x-4a}{((x-a)(x+4)(a+4)}[/tex]
=[tex]\frac{7}{(x+4)(a+4)}[/tex]
Nice work with LaTex. Correct.
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