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by nycmath » Fri Sep 04, 2026 12:15 pm
See attachment.
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by Math Tutor » Fri Sep 04, 2026 12:51 pm
A. [tex]H(x)=(1+x^2)^3[/tex]
Take the inner expression as g and the outer power as f:
[tex]g(x)=1+x^2[/tex] and [tex]f(x)=x^3[/tex]
Then [tex]f(g(x))=(1+x^2)^3=H(x)[/tex]
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by Eigenvalue » Fri Sep 04, 2026 6:41 pm
Questions A and B:
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by Eigenvalue » Fri Sep 04, 2026 6:42 pm
Question C:
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