MENU
No registration required!
Composite Functions
3 posts
• Page 1 of 1
Re: Composite Functions
by Eigenvalue » Tue Aug 25, 2026 5:48 pm
f(g(x)) is the same as f(x), with g(x) as the input
g(f(x)) is the same as g(x), with f)x) as the input
f(x)[tex]\sqrt[5]{x}[/tex]
g(x)=[tex]\frac{-x³}{x²-9}[/tex]
f(g(x))=[tex]\sqrt[5]{ \frac{-x³}{x²-9} }[/tex]
g(f(x)=[tex]\frac{ (\sqrt[5]{x})³ }{ (\sqrt[5]{x})²-9 }[/tex]
=[tex]\frac{ \sqrt[5]{x³} }{ \sqrt[5]{x}²-9 }[/tex]
g(f(x)) is the same as g(x), with f)x) as the input
f(x)[tex]\sqrt[5]{x}[/tex]
g(x)=[tex]\frac{-x³}{x²-9}[/tex]
f(g(x))=[tex]\sqrt[5]{ \frac{-x³}{x²-9} }[/tex]
g(f(x)=[tex]\frac{ (\sqrt[5]{x})³ }{ (\sqrt[5]{x})²-9 }[/tex]
=[tex]\frac{ \sqrt[5]{x³} }{ \sqrt[5]{x}²-9 }[/tex]
- Eigenvalue
- Posts: 336
- Joined: Mon Aug 10, 2026 10:38 pm
- Reputation: 161
Re: Composite Functions
by nycmath » Tue Aug 25, 2026 8:24 pm
Eigenvalue wrote:f(g(x)) is the same as f(x), with g(x) as the input
g(f(x)) is the same as g(x), with f)x) as the input
f(x)[tex]\sqrt[5]{x}[/tex]
g(x)=[tex]\frac{-x³}{x²-9}[/tex]
f(g(x))=[tex]\sqrt[5]{ \frac{-x³}{x²-9} }[/tex]
g(f(x)=[tex]\frac{ (\sqrt[5]{x})³ }{ (\sqrt[5]{x})²-9 }[/tex]
=[tex]\frac{ \sqrt[5]{x³} }{ \sqrt[5]{x}²-9 }[/tex]
Yep. That works.
3 posts
• Page 1 of 1
Return to Functions, Graphs, Derivatives
Who is online
Users browsing this forum: No registered users and 1 guest