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Compute Composition of Functions
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Re: Compute Composition of Functions
by Eigenvalue » Sun Aug 23, 2026 4:18 pm
A. [tex]\frac{(2x-1)²-(2a-1)²}{2x-1-(2a-1)}[/tex]
=[tex]\frac{4x²-4x-4a²+4a}{2x-2a}[/tex]
=[tex]\frac{(2x-2a)(2x+2a)-2(2x-2a)}{b}[/tex]
=2x+2a-2
B. [tex]\frac{(2x-1)²-(2a-1)²}{x-a}[/tex]
=[tex]\frac{4x²-4x-4a²+4a}{x-a}[/tex]
=[tex]\frac{(4x+4a)(x-a)-4(x-a)}{x-a}[/tex]
=4a+4x-4
=[tex]\frac{4x²-4x-4a²+4a}{2x-2a}[/tex]
=[tex]\frac{(2x-2a)(2x+2a)-2(2x-2a)}{b}[/tex]
=2x+2a-2
B. [tex]\frac{(2x-1)²-(2a-1)²}{x-a}[/tex]
=[tex]\frac{4x²-4x-4a²+4a}{x-a}[/tex]
=[tex]\frac{(4x+4a)(x-a)-4(x-a)}{x-a}[/tex]
=4a+4x-4
- Eigenvalue
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Re: Compute Composition of Functions
by nycmath » Sun Aug 23, 2026 9:06 pm
Eigenvalue wrote:A. [tex]\frac{(2x-1)²-(2a-1)²}{2x-1-(2a-1)}[/tex]
=[tex]\frac{4x²-4x-4a²+4a}{2x-2a}[/tex]
=[tex]\frac{(2x-2a)(2x+2a)-2(2x-2a)}{b}[/tex]
=2x+2a-2
B. [tex]\frac{(2x-1)²-(2a-1)²}{x-a}[/tex]
=[tex]\frac{4x²-4x-4a²+4a}{x-a}[/tex]
=[tex]\frac{(4x+4a)(x-a)-4(x-a)}{x-a}[/tex]
=4a+4x-4
You are awesome.
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