Eigenvalue wrote:1. f(g(x))=3(2[tex]\sqrt{x-3)}[/tex])+7
f(g(x))=6[tex]\sqrt{x-3}[/tex]+7
When x=3:
f(g(3))=6[tex]\sqrt{3-3}[/tex]+7=7
g(f(x))=2[tex]\sqrt{3x+7-3}[/tex]
g(f(x))=2[tex]\sqrt{3x+4}[/tex]
When x=3:
g(f(3))=2[tex]\sqrt{9+4}[/tex]=2[tex]\sqrt{13}[/tex]
Note: f(g(x)).does not have to equal g(f(x))
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