A New Fastest Method to Find Perfect Square Roots.

[Guest]

To find perfect square root of √3249

1st Step - Using the below formula by substituting 3249 at X to get m.

3249 / 72 = 45.125 …..
By ignoring the decimals, we get m = 45
We will take m value as m1 to input it in the below repeated subtraction series.
m1 = 45



2nd Step – Finding the Key Integer ‘c’ Using repeated subtraction series.
By substituting the m1 = 45 in the series we get,


Where m1 = 45
45 - 1 = 1
44 - 2 = 42
42 - 3 = 39
39 - 4 = 35
35 - 5 = 30
30 - 6 = 24
24 - 7 = 17
17 - 8 = 9
9 - 9 = 0
As per the ‘condition of series’ we cannot further subtract 0 – 10 = -10 since it gives negative value.
Therefore we stop the calculation at 9 – 9 = 0
Now, the last negative series of sequence at the above series is -9 and by converting it to positive integer, -9 × -1 = 9
we get Key Integer ‘c’ as 9
Therefore, c = 9


2th Step – Multiplying c by constant 6.

Therefore, 9 × 6 = 54
Now we get c = 54
Checking whether c is final answer by dividing 3249 by 54 . We found it is not divisible.
Therefore, we will proceed to below 3rd step of checking Rules of Finding ‘c.


3th Step – Checking the Rules of Finding ‘c’ to find perfect square root of c = 54

Note - The rule of finding c is available at the paper. For paper check the attached PDF.

√X = √3249 is divisible integer divisible by 3. Therefore it follows the fourth rule of finding c.
Fourth Rule - If the √ X is any odd integer and is divisible by 3, then the final answer c will be adding s by 3 i.e. ‘c + 3'.


54 + 3 = 57

Since 3249 is divisible by 57
Therefore, √3249 = 57

[Guest]

To find perfect square root of √3249

1st Step - Using the below formula by substituting 3249 at X to get m.

3249 / 72 = 45.125 …..
By ignoring the decimals, we get m = 45
We will take m value as m1 to input it in the below repeated subtraction series.
m1 = 45



2nd Step – Finding the Key Integer ‘c’ Using repeated subtraction series.
By substituting the m1 = 45 in the series we get,


Where m1 = 45
45 - 1 = 1
44 - 2 = 42
42 - 3 = 39
39 - 4 = 35
35 - 5 = 30
30 - 6 = 24
24 - 7 = 17
17 - 8 = 9
9 - 9 = 0
As per the ‘condition of series’ we cannot further subtract 0 – 10 = -10 since it gives negative value.
Therefore we stop the calculation at 9 – 9 = 0
Now, the last negative series of sequence at the above series is -9 and by converting it to positive integer, -9 × -1 = 9
we get Key Integer ‘c’ as 9
Therefore, c = 9


2th Step – Multiplying c by constant 6.

Therefore, 9 × 6 = 54
Now we get c = 54
Checking whether c is final answer by dividing 3249 by 54 . We found it is not divisible.
Therefore, we will proceed to below 3rd step of checking Rules of Finding ‘c.


3th Step – Checking the Rules of Finding ‘c’ to find perfect square root of c = 54

Note - The rule of finding c is available at the paper. For paper check the attached PDF.

√X = √3249 is divisible integer divisible by 3. Therefore it follows the fourth rule of finding c.
Fourth Rule - If the √ X is any odd integer and is divisible by 3, then the final answer c will be adding s by 3 i.e. ‘c + 3'.


54 + 3 = 57

Since 3249 is divisible by 57
Therefore, √3249 = 57

Ignore the previous PDF.....Get the corrected new pdf from below attachment at this quote.