If 2/5 of a number exceeds 1/7 of the same number by 36

[Guest]

If 2/5 of a number exceeds 1/7 of the same number by 36.
Find the number.

[Jonasmathwork]

Solution: Let the number is x
then 2/5 of x=2x/5
x exceeds 1/7 of number 36

there for the equation 2x/5=x/7+36
2x/5-x/7-36=0
9(x-140)/35=0

x=140

the number is 140.

[jackwilson]

Yes correct method he used.

[burgess]

Solution: Let the number is x
then 2/5 of x=2x/5
x exceeds 1/7 of number 36

there for the equation 2x/5=x/7+36
2x/5-x/7-36=0
9(x-140)/35=0

x=140

the number is 140.

Yes this method is correct

[Guest]

I agree that the method is correct but I would have written it a little differently.

Yes, calling "the number" x, "2/5 of the number" is 2x/5.
Yes, "1/7 of that same number" is x/7.

I would have written "A exceeds B by C'" as A- B= C so "2/5 of a number exceeds 1/7 of the same number by 36" as 2x/5- x/7= 36 immediately.

Then 2(7)x/5(7)- 5x/7(5)= 14x/35- 5x/35= 9x/35= 36.

x= 36(35/9)= (36/9)(35)= 4(35)= 140.

That is, of course, exactly what Jonasmathwork got.

[Guest]

If 2/5 of a number exceeds 1/7 of the same number by 36.
Find the number.

Let the required number be x.

[tex]\frac{2}{5} * x = \frac{1}{7} * x + 36[/tex]

[tex]\frac{2}{5} * x - \frac{1}{7} * x = \frac{14}{35} * x - \frac{5}{35} * x = \frac{9}{35} * x = 36[/tex]

[tex]x = 36 * \frac{35}{9} = 4 * 35 = 140[/tex]

Answer: [tex]x = 140[/tex]

[Guest]

Not the clearest answer

[Guest]

Not the clearest answer

seems like this

[Guest]

A few more words could have been used to make it clearer to those who are not already adept at this kind of problem.
Mathematical equations are very terse!

[Guest]

Just to stick my oar in:
Let "the number" be "x". Then "2/5 of a number","2/5 of x", is 2x/5. "1/7 of the same number", "1/7 of x", is x/7.

"2/5 of a number exceeds 1/7 of the same number by 36" is 2x/5- x/7= 36.

Instead of getting a common denominator and adding the fractions, I would clear the fractions entirely by multiplying both sides by 5(7)= 35.
35(2x/5)- 35(x/7)= 35(36).
14x- 5x= 1260.
9x= 1260
x= 1260/9= 140.

[Angus53]

If 2/5 of a number exceeds 1/7 of the same number by 36, we can represent this algebraically. Let's denote the number as "x."

According to the given condition:
2/5 * x - 1/7 * x = 36

To solve, first find a common denominator for 5 and 7, which is 35:
(14/35)x - (5/35)x = 36
(14x/35) - (5x/35) = 36

Now, combine the fractions:
(14x - 5x) / 35 = 36

Simplify:
9x / 35 = 36

Multiply both sides by 35 to isolate "x":
9x = 36 * 35
9x = 1260

Divide both sides by 9:
x = 1260 / 9
x = 140

So, the number is 140.

[Guest]

Let's denote the number as x. According to the given information:

2/5x−1/7x=36

To solve for x, first, let's find a common denominator for 2/5 and 1/7, which is 35. Then, rewrite the equation:

14/35x−5/35x=36
14/35x−5/35x=36
9/35x=36

Now, let's isolate x:

9x=36×35
9x=1260
x=1260/9
x=140

So, the number is 140.

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