Fraction problem

Fraction problem

Postby sam2007 » Fri Jul 26, 2019 11:43 am

I need understandable ans of below problem pls

In a bag full of small balls, 1/4 of these balls are green, 1/8 are blue, 1/12 are yellow and the remaining 26 white. How many balls are blue ?
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Re: fraction problem

Postby nathi123 » Fri Jul 26, 2019 12:16 pm

Let all balls are x, then [tex]x-(\frac{x}{4}+\frac{x}{8}+\frac{x}{12})=26 \Leftrightarrow x-\frac{11x}{24}=26\Leftrightarrow[/tex]
[tex]\frac{13x}{24} = 26 |:13\Leftrightarrow x=2.24\Leftrightarrow x=48[/tex] . And blue balls are [tex]\frac{48}{8}=6[/tex].

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Re: fraction problem

Postby sam2007 » Fri Jul 26, 2019 12:38 pm

where this 13x came from ? pls explain

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Re: Fraction problem

Postby Guest » Sat Jul 27, 2019 11:48 am

x-[tex]\frac{11x}{24}[/tex]=

=[tex]\frac{x}{1}[/tex]-[tex]\frac{11x}{24}[/tex]=

=[tex]\frac{24x}{24}[/tex]-[tex]\frac{11x}{24}[/tex]=

=[tex]\frac{24x-11x}{24}[/tex]=

=[tex]\frac{13x}{24}[/tex]
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Re: Fraction problem

Postby HallsofIvy » Sat Dec 21, 2019 2:05 pm

Equivalently, [tex]x- \frac{11}{24}x= \left(1- \frac{11}{24}\right)x= \left(\frac{24}{24}- \frac{11}{24}\right)x= \left(\frac{24- 11}{24}\right)x= \frac{13}{24}x[/tex].

The "13" is 24- 11.

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Re: Fraction problem

Postby trishadasc » Tue Dec 24, 2019 12:44 am

Great Post.thank you for great solution :)
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Re: Fraction problem

Postby shreyathakare » Fri Dec 27, 2019 12:58 am

Thanks for the information.

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Re: Fraction problem

Postby Poonaam » Mon Jan 06, 2020 5:37 am

Hi!
Excellent share.. keep sharing!!


Thank you!!

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