Subtract Fractions

[nycmath]

See attachment.

Show your work by hand. No calculator. No app. No online help. Solve the old fashioned way.

[Eigenvalue]

Questions A and B:

[Guest]

A=100+[tex]\frac{7}{8} -(66+ \frac{1}{3}[/tex]) =

=34+ ([tex]\frac{7}{8} -\frac{1}{3}[/tex])=

=34+[tex]\frac{21-8}{24}[/tex]=

=34+[tex]\frac{13}{24} = 34\frac{13}{24}[/tex]

[Guest]

A=100+[tex]\frac{7}{8} -(66+ \frac{1}{3}[/tex]) =

=34+ ([tex]\frac{7}{8} -\frac{1}{3}[/tex])=

=34+[tex]\frac{21-8}{24}[/tex]=

=34+[tex]\frac{13}{24} = 34\frac{13}{24}[/tex]

[Guest]

A=100+[tex]\frac{7}{8} -(66+ \frac{1}{3}[/tex]) =

=34+ ([tex]\frac{7}{8} -\frac{1}{3}[/tex])=

=34+[tex]\frac{21-8}{24}[/tex]=

=34+[tex]\frac{13}{24} = 34\frac{13}{24}[/tex]

[nycmath]

Questions A and B:

Nice work but lacking explanation in words.

[nycmath]

A=100+[tex]\frac{7}{8} -(66+ \frac{1}{3}[/tex]) =

=34+ ([tex]\frac{7}{8} -\frac{1}{3}[/tex])=

=34+[tex]\frac{21-8}{24}[/tex]=

=34+[tex]\frac{13}{24} = 34\frac{13}{24}[/tex]

This message pertains to all three replies. We both know what you did here. However, I think posting TOO MANY questions has led to the lack of effort to explain in words what you are doing. It is my understanding that this can easily change if less questions are posted. So, why don't we try that?