Fractions multiplication

Fractions multiplication

Postby Math Tutor » Fri Jan 04, 2008 5:21 am

[tex]\frac{1}{2} . \frac{2}{3} = ?[/tex]

[tex]\frac{20}{21} . \frac{3}{10} = ?[/tex]

[tex]\frac{10}{3} . 4\frac{15}{8} = ?[/tex]

[tex]2\frac{8}{9} . 5\frac{1}{3} = ?[/tex]
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Re: Fractions multiplication

Postby dduclam » Tue Mar 25, 2008 2:26 am

teacher wrote: [tex]\frac{1}{2} . \frac{2}{3} = ?[/tex]

[tex]\frac{20}{21} . \frac{3}{10} = ?[/tex]

[tex]\frac{10}{3} . 4\frac{15}{8} = ?[/tex]

[tex]2\frac{8}{9} . 5\frac{1}{3} = ?[/tex]


[tex]\frac{1}{2} . \frac{2}{3} = \frac1{3}[/tex]

[tex]\frac{20}{21} . \frac{3}{10} = \frac2{7}[/tex]

[tex]\frac{10}{3} . 4\frac{15}{8} = \frac{235}{12}[/tex]

[tex]2\frac{8}{9} . 5\frac{1}{3} = \frac{416}{27}[/tex]

:roll:

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Re: Fractions multiplication

Postby Math Tutor » Tue Dec 14, 2010 8:02 pm

[tex]\frac{n-2}{2n}-\frac{n+4}{2n+5}=0[/tex]

[tex]\frac{(n-2)(2n+5)}{2n(2n+5)}-\frac{2n(n+4)}{2n(2n+5)}=0[/tex]

[tex]\frac{(n-2)(2n+5) - 2n(n+4)}{2n(2n+5)}=0[/tex]

[tex]\frac{2n^2 + 5n - 4n - 10 - 2n^2 -8n}{2n(2n+5)}=0[/tex]

[tex]\frac{5n - 4n - 10 -8n}{2n(2n+5)}=0[/tex]

there are solution of the fraction equation only if
[tex]5n - 4n - 10 -8n=0[/tex]
or [tex]-7n=10[/tex]
or [tex]n=-\frac{10}{7}[/tex]

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Re: Fractions multiplication

Postby Math Tutor » Wed Dec 15, 2010 8:19 am

Did you understand the decision of your fraction problem?

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Re: Fractions multiplication

Postby burgess » Mon Jul 14, 2014 6:28 am

Math Tutor wrote:[tex]\frac{1}{2} . \frac{2}{3} = ?[/tex]

[tex]\frac{20}{21} . \frac{3}{10} = ?[/tex]

[tex]\frac{10}{3} . 4\frac{15}{8} = ?[/tex]

[tex]2\frac{8}{9} . 5\frac{1}{3} = ?[/tex]


[tex]\frac{1}{2} . \frac{2}{3} = 1/3[/tex]

[tex]\frac{20}{21} . \frac{3}{10} = 2/7[/tex]

[tex]\frac{10}{3} . 4\frac{15}{8} = 235/12[/tex]

[tex]2\frac{8}{9} . 5\frac{1}{3} = 416/27[/tex]

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Re: Fractions multiplication

Postby Jason85 » Mon Aug 11, 2014 10:00 am

Here is a solution for your question:

solution.png
solution.png (6.59 KiB) Viewed 2898 times
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