Good night!
a)
Let's fix the origin of the coordinates in the base of SW mast.
So, calling A the SW mast top and B the NE mast top:
A(0,0,23) and
B(16,12,8), right?
The distance between them:
[tex]d^2=16^2+12^2+(23-8)^2[/tex]
[tex]d^2=256+144+225[/tex]
[tex]d=\sqrt{625}=25[/tex]
So, 25 is right
b)
From SW to NE, the 'high' of the middle point is:
[tex]\frac{23+8}{2}=\frac{31}{2}=15,5[/tex]
From SE to NW, the 'high'of the middle point is:
[tex]\frac{28+5}{2}=\frac{33}{2}=16,5[/tex]
So, the sparrow is 16,5-15,5=1,0 below the robin.
c)
Try to see that the figure is two trapezes.
They intercept one to each other 6 m distant from the East edge.
And the distance between each cable, is 3.
A figure to try to help
- Captura de Tela 2019-10-22 às 21.48.08.png (256.74 KiB) Viewed 280 times