Finding the area of the shaded region

[Guest]

Please refer to the image attached below. I understand that this question can be solved using secondary school radians method, but is there a primary school/even more elementary of solving this question? Thanks so much for your help!!!

[Guest]

The exact answer is [tex]7^2(\pi/12+2-\sqrt{3})[/tex] there is no way to get the square root of 3 by primary school methods, you need to know some trigonometry or pythagoras.

[Guest]

The exact answer is [tex]7^2(\pi/12+2-\sqrt{3})[/tex] there is no way to get the square root of 3 by primary school methods, you need to know some trigonometry or pythagoras.

Hello, but WHY can't we use primary school methods?

[Guest]

By primary school methods you can get rationals by considering areas of squares and triangles, you can get expressions involving pi by considering areas of circles or portions of circles. There is no way to get the square root of 3, there is no simple operation or fact at your disposal which will allow you to create expressions that have square roots in them. looking at areas of circles squares and triangles, adding, subtracting, or takingfractional amounts of them like a quarter of a circle or something doesnt get you square roots. the squre root must come from a more sophisticated tool like pythagoras