Theorem that in a triangle the sum of every two sides bigger

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Theorem that in a triangle the sum of every two sides bigger

Postby alex » Wed Oct 12, 2005 11:47 am

Does someone knows the proof of the theorem that in a triangle the sum of every two sides is bigger than the length of the third site
alex
 

Re: theorem

Postby MathTeacher01 » Wed Mar 09, 2011 5:31 pm

consider the triangle ABC and its height BH. The height divides the base into AH and HC.
AB is hypothenuse of triangle ABH. Therefore AB > AH
BC is hypothenuse of triangle BCH. Therefore BC > HH
AB + BC > AH + HC
Therfore: AB + BC > AC

MathTeacher01
 
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Re: theorem

Postby alex » Thu Mar 10, 2011 2:16 am

Thank you for the proof of the theorem. Is the proof valid when we have an acute triangle.

alex
 

Re: Theorem that in a triangle the sum of every two sides bi

Postby leesajohnson » Mon Jan 25, 2016 7:28 am

Let a triangle be ABC and its height is AE

AB+BC > AE+ EC
AB+BC > AC

leesajohnson
 


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