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Angle Bisect

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Angle Bisect

Postby nycmath » Sun Sep 20, 2026 8:32 am

See attachment.
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nycmath
 
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Re: Angle Bisect

Postby Eigenvalue » Sun Sep 20, 2026 11:00 am

[tex]\vec{AC}[/tex] bisects [tex]\angle[/tex]BAD, therefore [tex]\angle[/tex]DAC=[tex]\angle[/tex]CAB and [tex]\angle[/tex]DAC+m[tex]\angle[/tex]CAB=[tex]\angle[/tex]BAD

m[tex]\angle[/tex]CAB=m[tex]\angle[/tex]DAC=x°
[tex]\angle[/tex]BAD=80°

Substitute in the values for m[tex]\angle[/tex]CAB
x°+x°=80°
x+x=80
2x=80
x=40
m[tex]\angle[/tex]CAB=[tex]\angle[/tex]BAC=40°

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Re: Angle Bisect

Postby nycmath » Sun Sep 20, 2026 6:22 pm

Eigenvalue wrote:[tex]\vec{AC}[/tex] bisects [tex]\angle[/tex]BAD, therefore [tex]\angle[/tex]DAC=[tex]\angle[/tex]CAB and [tex]\angle[/tex]DAC+m[tex]\angle[/tex]CAB=[tex]\angle[/tex]BAD

m[tex]\angle[/tex]CAB=m[tex]\angle[/tex]DAC=x°
[tex]\angle[/tex]BAD=80°

Substitute in the values for m[tex]\angle[/tex]CAB
x°+x°=80°
x+x=80
2x=80
x=40
m[tex]\angle[/tex]CAB=[tex]\angle[/tex]BAC=40°


Correct and direct.

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