by nycmath » Wed Aug 26, 2026 4:28 am
by Eigenvalue » Thu Sep 24, 2026 12:38 am
by nycmath » Thu Sep 24, 2026 4:13 am
Eigenvalue wrote:Use the formula for area of a circle: A=[tex]\fracπr²r=25A=π(25)²=625π ft²
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