by shyamjayakannan » Sun Feb 02, 2025 3:09 pm
[tex]\triangle ADE[/tex] is isosceles, so [tex]\angle AED=\frac{180 ^\circ-28 ^\circ }{2}=\boxed{76 ^\circ}[/tex]
[tex]\triangle ABE[/tex] is isosceles, so [tex]\angle ABE=\frac{180 ^\circ-(45 ^\circ +17 ^\circ) }{2}=59 ^\circ \Rightarrow \angle CBE=90 ^\circ -59 ^\circ =\boxed{31 ^\circ }[/tex]