SAT cylinder problem

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SAT cylinder problem

Postby Guest » Wed Dec 11, 2013 3:12 am

6. Points A and B are on the top and bottom edges of a cylindrical roll of paper of height 8 and circumference 12. A and B are diagonally opposite each other. The paper is cut along line C and opened out. How far apart are A and B on the flat surface?

I'm not sure how they found the diameter to equal 6 if C=12
Please help if you can.
Guest
 

Re: SAT cylinder problem

Postby Guest » Wed Dec 11, 2013 8:27 am

A wee diagram would help.....
I assume C is a line from A to B around the roll....as in a spiral....
A and B are diagonally opposite so half way round so if circumference is 12 then they are 6 apart as looked at round the circumference of the roll.
When you cut along the line C from A to B you end up with a right angled triangle of 6 on one side and 8 on the other (8 is the height of the roll)

On the flat Distance from A to B will be the length of the hypotenuse of this triangle.

that is......squareroot of 6 squared plus 8 squared

equals squareroot of 36 + 64
equals squareroot of 100

equals..... 10 ........

Simple
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