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Prove that:
|a+b|<=|a|+|b|
and when |a + b| = |a| + |b| ?
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Absolute Value Inequality |a+b|<=|a|+|b|
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Re: Absolute Value Inequality |a+b|<=|a|+|b|
by perfectmath » Fri Jun 29, 2012 12:37 am
[tex]|a+b|=|a|+|b|[/tex] when [tex]ab \ge 0[/tex].
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perfectmath - Posts: 25
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