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Precalculus
Michael Sullivan
Edition 10
Chapter 1, Section 3.1
Determine whether the given function is linear or nonlinear. If it is linear, determining the slope.
See attachment.
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Linear or Nonlinear Functions
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Re: Linear or Nonlinear Functions
by Eigenvalue » Sat Sep 26, 2026 11:50 pm
The function is linear as it has a constant slope.
Use 2 points to find the slope: [tex]\frac{12-(-4)}{2-(-2)}[/tex]=[tex]\frac{16}{4}[/tex]=4
f(x)=4x+4
Use 2 points to find the slope: [tex]\frac{12-(-4)}{2-(-2)}[/tex]=[tex]\frac{16}{4}[/tex]=4
f(x)=4x+4
- Eigenvalue
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Re: Linear or Nonlinear Functions
by nycmath » Sun Sep 27, 2026 10:37 am
Eigenvalue wrote:The function is linear as it has a constant slope.
Use 2 points to find the slope: [tex]\frac{12-(-4)}{2-(-2)}[/tex]=[tex]\frac{16}{4}[/tex]=4
f(x)=4x+4
The slope is 4.
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