by Math Tutor » Wed Aug 19, 2026 6:03 am
I'll take graphs #12 and #19.
A. Vertical line test
A graph is the graph of a function exactly when no vertical line crosses it more than once (one input, one output). Sliding a vertical line across #12 and across #19, it always meets the curve in exactly one point, so both are functions. (For contrast, #11, #15 and #16 all fail the test - a vertical line hits them twice.)
B1. Graph #12 (the curve rising left to right, flattening onto the x-axis on the left)
1. Domain and range. The arrows say the curve continues forever both ways, so the domain is [tex]\{x\,|\,x \in \mathbb{R}\}=(-\infty,\infty)[/tex]. Going left the curve gets closer and closer to the x-axis but never reaches it, so [tex]y=0[/tex] is a horizontal asymptote and the range is [tex]\{y\,|\,y>0\}=(0,\infty)[/tex].
2. Intercepts. It crosses the y-axis at [tex](0,1)[/tex]. There is no x-intercept, since the graph never actually touches [tex]y=0[/tex].
3. Symmetry. None. The left half is nothing like the right half, so there is no y-axis symmetry and no origin symmetry.
B2. Graph #19 (the "plateau": rises to [tex](-1,2)[/tex], flat across to [tex](1,2)[/tex], then falls)
1. Domain and range. Again the arrows continue forever, so the domain is [tex](-\infty,\infty)[/tex]. The highest point reached is [tex]y=2[/tex] (the whole flat top), and the graph drops without bound on both ends, so the range is [tex]\{y\,|\,y \le 2\}=(-\infty,2][/tex].
2. Intercepts. The graph meets the x-axis at [tex](-3,0)[/tex] and [tex](3,0)[/tex], and it meets the y-axis at [tex](0,2)[/tex].
3. Symmetry. Symmetric with respect to the y-axis: whatever happens at [tex]x[/tex] happens at [tex]-x[/tex] (for example [tex](-1,2)[/tex] and [tex](1,2)[/tex], [tex](-3,0)[/tex] and [tex](3,0)[/tex]), so [tex]f(-x)=f(x)[/tex] and the function is even. Not symmetric about the origin, and not about the x-axis.
One useful remark for part 3 in general: apart from the trivial case, no graph of a function can be symmetric with respect to the x-axis, because reflecting a point [tex](a,b)[/tex] to [tex](a,-b)[/tex] would put two points on the same vertical line - exactly what the vertical line test forbids.